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+/***************************************************************************
+ kssun.cpp - K Desktop Planetarium
+ -------------------
+ begin : Sun Jul 22 2001
+ copyright : (C) 2001 by Jason Harris
+ email : jharris@30doradus.org
+ ***************************************************************************/
+
+/***************************************************************************
+ * *
+ * This program is free software; you can redistribute it and/or modify *
+ * it under the terms of the GNU General Public License as published by *
+ * the Free Software Foundation; either version 2 of the License, or *
+ * (at your option) any later version. *
+ * *
+ ***************************************************************************/
+
+#include <math.h>
+#include <qdatetime.h>
+
+#include "kssun.h"
+#include "ksutils.h"
+#include "ksnumbers.h"
+#include "kstarsdatetime.h"
+
+KSSun::KSSun( KStarsData *kd, QString fn, double pSize ) : KSPlanet( kd, I18N_NOOP( "Sun" ), fn, pSize ) {
+ /*
+ JD0 = 2447892.5; //Jan 1, 1990
+ eclong0 = 279.403303; //mean ecliptic longitude at JD0
+ plong0 = 282.768422; //longitude of sun at perigee for JD0
+ e0 = 0.016713; //eccentricity of Earth's orbit at JD0
+ */
+ setMag( -26.73 );
+}
+
+bool KSSun::loadData() {
+// kdDebug() << k_funcinfo << endl;
+ return (odm.loadData("earth") != 0);
+}
+
+bool KSSun::findGeocentricPosition( const KSNumbers *num, const KSPlanetBase *Earth ) {
+ if (Earth) {
+ //
+ // For the precision we need, the earth's orbit is circular.
+ // So don't bother to iterate like KSPlanet does. Just subtract
+ // The current delay and recompute (once).
+ //
+ double delay = (.0057755183 * Earth->rsun()) / 365250.0;
+
+ //
+ // MHH 2002-02-04 I don't like this. But it avoids code duplication.
+ // Maybe we can find a better way.
+ //
+ const KSPlanet *pEarth = dynamic_cast<const KSPlanet *>(Earth);
+ /* FIXME: if you use pEarth at some point again, make sure you
+ check for 0L after the dynamic_cast! */
+ EclipticPosition trialpos;
+ pEarth->calcEcliptic(num->julianMillenia() - delay, trialpos);
+
+ setEcLong( trialpos.longitude.Degrees() + 180.0 );
+ setEcLong( ecLong()->reduce().Degrees() );
+ setEcLat( -1.0*trialpos.latitude.Degrees() );
+
+ } else {
+ double sum[6];
+ dms EarthLong, EarthLat; //heliocentric coords of Earth
+ OrbitDataColl * odc;
+ double T = num->julianMillenia(); //Julian millenia since J2000
+ double Tpow[6];
+
+ Tpow[0] = 1.0;
+ for (int i=1; i<6; ++i) {
+ Tpow[i] = Tpow[i-1] * T;
+ }
+ //First, find heliocentric coordinates
+
+ if (!(odc = odm.loadData("earth"))) return false;
+
+ //Ecliptic Longitude
+ for (int i=0; i<6; ++i) {
+ sum[i] = 0.0;
+ for (uint j = 0; j < odc->Lon[i].size(); ++j) {
+ sum[i] += odc->Lon[i][j]->A * cos( odc->Lon[i][j]->B + odc->Lon[i][j]->C*T );
+ }
+ sum[i] *= Tpow[i];
+ //kdDebug() << name() << " : sum[" << i << "] = " << sum[i] <<endl;
+ }
+
+ EarthLong.setRadians( sum[0] + sum[1] + sum[2] +
+ sum[3] + sum[4] + sum[5] );
+ EarthLong.setD( EarthLong.reduce().Degrees() );
+
+ //Compute Ecliptic Latitude
+ for (int i=0; i<6; ++i) {
+ sum[i] = 0.0;
+ for (uint j = 0; j < odc->Lat[i].size(); ++j) {
+ sum[i] += odc->Lat[i][j]->A * cos( odc->Lat[i][j]->B + odc->Lat[i][j]->C*T );
+ }
+ sum[i] *= Tpow[i];
+ }
+
+
+ EarthLat.setRadians( sum[0] + sum[1] + sum[2] + sum[3] +
+ sum[4] + sum[5] );
+
+ //Compute Heliocentric Distance
+ for (int i=0; i<6; ++i) {
+ sum[i] = 0.0;
+ for (uint j = 0; j < odc->Dst[i].size(); ++j) {
+ sum[i] += odc->Dst[i][j]->A * cos( odc->Dst[i][j]->B + odc->Dst[i][j]->C*T );
+ }
+ sum[i] *= Tpow[i];
+ }
+
+ ep.radius = sum[0] + sum[1] + sum[2] + sum[3] + sum[4] + sum[5];
+
+ setEcLong( EarthLong.Degrees() + 180.0 );
+ setEcLong( ecLong()->reduce().Degrees() );
+ setEcLat( -1.0*EarthLat.Degrees() );
+ }
+
+ //Finally, convert Ecliptic coords to Ra, Dec. Ecliptic latitude is zero, by definition
+ EclipticToEquatorial( num->obliquity() );
+
+ nutate(num);
+ aberrate(num);
+
+ // We obtain the apparent geocentric ecliptic coordinates. That is, after
+ // nutation and aberration have been applied.
+ EquatorialToEcliptic( num->obliquity() );
+
+ //Determine the position angle
+ findPA( num );
+
+ return true;
+}
+
+long double KSSun::springEquinox(int year) {
+ return equinox(year, 18, 3, 0.);
+}
+
+long double KSSun::summerSolstice(int year) {
+ return equinox(year, 18, 6, 90.);
+}
+
+long double KSSun::autumnEquinox(int year) {
+ return equinox(year, 19, 9, 180.);
+}
+
+long double KSSun::winterSolstice(int year) {
+ return equinox(year, 18, 12, 270.);
+}
+
+long double KSSun::equinox(int year, int d, int m, double angle) {
+ long double jd0[5];
+ long double eclipticLongitude[5];
+
+ for(int i = 0; i<5; ++i) {
+ jd0[i] = KStarsDateTime( ExtDate(year,m,d+i), QTime(0,0,0) ).djd();
+ KSNumbers *ksn = new KSNumbers(jd0[i]);
+ //FIXME this is the Earth position
+ findGeocentricPosition( ksn );
+ delete ksn;
+ eclipticLongitude[i] = (long double)ecLong()->Degrees();
+ }
+
+ return KSUtils::lagrangeInterpolation( eclipticLongitude, jd0, 5, angle );
+}